Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.
Ncert Math Solutions Class 6th Chapter 11 Algebra Exercise 11.2 Question 5
To find sum of three numbers 14, 27 and 13, we can have two ways:
(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus, (14 + 27) + 13 = 14 + (27 + 13)
This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables a, b and c.
Answer:
To add three numbers a, b and c. We may add a and b first and then add c to it to get the total sum of a, b and c.
or
We may add b and c first and then add a to it to get the total sum of a, b and c.
It means that (a+b) + c = a + (b+c)
Ncert Math Solutions Class 6th Chapter 11 Algebra Exercise 11.2 Question 4
The diameter of a circle is a line which joins two points on the circle and also passes through the centre of the circle. AB is a diameter of the circle; C is its centre. Express the diameter of the circle (d) in terms of its radius (r).
Ncert Math Solutions Class 6th Chapter 11 Algebra Exercise 11.2 Question 3
A cube is a three-dimensional figure as shown in figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by
. Find the formula for the total length of the edges of a cube.
Ncert Math Solutions Class 6th Chapter 11 Algebra Exercise 11.2 Question 2
The side of a regular hexagon is denoted by
. Express the perimeter of the hexagon using
.
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