- Write down a pair of integers whose:
(a) sum is –7 (b) difference is –10 (c) sum is 0
Answer:
(a) (-4) + (-3 ) = -7 or (-10) + (3) = -7
(b) -20 – (-10) = -20 + 10 = -10 or -7 – (3) = -10
(c) (-5) + 5 = 0 or 10 + (-10) = 0
2. (a) Write a pair of negative integers whose difference gives 8.
Answer:
-2 – (-10) = -2 + 10 = 8 or -3 – (-11) = -3 + 11 = 8
2. (b) Write a negative integer and a positive integer whose sum is –5.
Answer:
(-10) + (5) = -5 or (-20) + (15) = -5
2. (c) Write a negative integer and a positive integer whose difference is –3.
Answer:
(-1) – (2) = -3
3. In a quiz, team A scored – 40, 10, 0 and team B scored 10, 0, – 40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?
Answer:
Team A scored: (-40) + (10) + (0) = -30
Team B scored: (10) + (0) + (-40) = -30
Both teams scored equally. We can add integers in any order because addition is associative in nature which means (a+b) +c = (b+c) + a
4. Fill in the blanks to make the following statements true:
(i) (–5) + (– 8) = (– 8) + (……-5……) = -13
(ii) –53 + ……0…… = –53
(iii) 17 + ……(-17)…… = 0
(iv) [13 + (– 12)] + (……-7……) = 13 + [(–12) + (–7)] = -6
(v) (– 4) + [15 + (–3)] = [– 4 + 15] + ……(-3)…… = 8
Khan says
It is of class 7i want of class 6 and I don’t want this
Jashan says
Here you can have access to class 6th solutions. Thanks
https://mathinstructor.net/ncert-solutions-math/class-6th/