Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.
(a) 5m = 60 (10, 5, 12, 15)
12 is the solution for this equation because L.H.S=R.H.S for m=12.
For m = 10.
L.H.S
R.H.S
For m = 5
L.H.S
R.H.S
For m = 15
L.H.S
R.H.S
(b) n + 12 = 20 (12, 8, 20, 0)
8 is the solution for this equation because L.H.S=R.H.S for n=8.
For n = 12
L.H.S
R.H.S
For n = 20
L.H.S
R.H.S
For n = 0
L.H.S
R.H.S
(c) p – 5 = 5 (0, 10, 5 – 5)
p = 10 is the solution for this equation because for p = 10, L.H.S=R.H.S
For p = 0
L.H.S
R.H.S
For p = 5
L.H.S
R.H.S
For p = -5
L.H.S
R.H.S
(d)
(7, 2, 10, 14)
q = 14 is the solution for this equation because L.H.S = R.H.S for q=14.
For q=7
L.H.S
R.H.S
For q=2
L.H.S
R.H.S
For q=10
L.H.S
R.H.S
(e) r – 4 = 0 (4, – 4, 8, 0)
r = 4 is the solution of this equation because L.H.S = R.H.S for r=4.
For r = -4
L.H.S
R.H.S
For r = 8
L.H.S
R.H.S
For r = 0
L.H.S
R.H.S
(f) x + 4 = 2 (– 2, 0, 2, 4)
x = -2 is the solution of this equation because L.H.S = R.H.S for x = -2
For x = 0
L.H.S
R.H.S
For x = 2
L.H.S
R.H.S
For x = 4
L.H.S
R.H.S
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