D and E are points on sides AB and AC respectively of
such that ar (DBC) = ar (EBC). Prove that
.
Solution:
D and E are points on the sides AB and AC respectively of
.
It is given that
(1)
and
also lie on the same base BC. (2)
From (1) and (2), we can say that
(Two triangles having the same base and equal areas lie between the same parallels.)
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