**Areas related to Circles ncert solutions Chapter 12 Exercise 12.2 Question 7**

**7. **A chord of a circle of radius 12 cm subtends an angle of at the center. Find the area of the corresponding segment of the circle. (Use and )

**Solution:**

Area of segment ACB= Area of minor sector ACBO - Area of **(1)**

Area of minor sector ACBO=

**(2)**

In and

AO=OB {Radii of circle}

{Each }

OD = OD (Common side)

Therefore, by **RHS congruency** axiom,

{Corresponding angles of congruent triangles are equal}

In

**cm**

Also,

**cm**

Area of

Area of **cm (3)**

Putting equation **(2) and (3) **in equation **(1)** , we get

**Area of segment ACB**