Circles ncert solutions Chapter 10 Exercise 10.2 Question 1
1. From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the center is 25 cm. The radius of the circle is:
(A) 7 cm (B) 12 cm (C) 15 cm (D) 24.5 cm
It is given that BQ = 24 cm and OQ = 25 cm
is right angled triangle because tangent is always perpendicular to radius of the circle.
Therefore, we can apply Pythagoras theorem on
By, Pythagoras theorem, we can say that
cm
Therefore, radius of circle is equal to 7 cm.
Therefore, answer is (A)
john says
there is a fault in question
the distance of Q from the center is 25 cm*
Jashan says
Thanks for letting me know about the error. I have fixed the error.