Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of
(see figure). Show that:
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Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of
(see figure). Show that:
AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that
(i) AD bisects BC (ii) AD bisects ∠ A.
and
are two isosceles triangles on the same base BC and vertices A and D are on the
same side of BC (see Figure). If AD is extended to intersect BC at P, show that