Diagonal of a square ABCD is equal to 8 cm. Area of ABCD is equal to?

**(A) **8 **(B) **16

**(C) **32 **(D)** 64

**(E)** None of the above

Let side of square ABCD = s

Area of square ABCD = side side

ABCD is a square which means that is right angled at B.

Therefore, ** (Pythagoras theorem)**

Hence, the answer is **(C)**