Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
Solution:
Let’s find the L.C.M of 6, 15 and 18.
Therefore, L.C.M of 6, 15 and 18
It means that 90 is the smallest number which when divided by 6, 15 and 18 leaves remainder 0 in each case.
Therefore, smallest number which when divided by 6, 15 and 18 leaves remainder 5 = 90 + 5 = 95
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