Frequency distribution table shows concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.
Find the probability of the concentration of sulphur dioxide in the interval 0.12 – 0.16 on any of these days.
Answer:
Let E be the event that concentration of sulphur dioxide is in the interval 0.12-0.16 on any of the 30 days.
P(E) = (Number of days for which concentration of
is in the interval 0.12-0.16 from 30 days / Total number of days)
Leave a Reply