In figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that
(i) ar (ACB) = ar (ACF)
(ii) ar (AEDF) = ar (ABCDE)
We have (Given)
We can see that and are on the same base and between the same parallels AC and BF.
(Triangles on the same base and between the same parallels are equal in area.)
We have proved above that