The taxi fare in a city is as follows: For the first kilometre, the fare is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as
km and total fare as Rs y, write a linear equation for this information, and draw its graph.
Solution:
Total distance covered
km
Fare collected for 1st km = Rs 8
Fare collected for remaining
kms at the rate of Rs 5 per km = Rs
Total fare collected = Rs
According to given condition, we have
This equation represents the given situation.
To draw graph of
, we will find 3 or 4 set of solutions.
Putting
in the equation
, we get
Therefore,
is one of the infinite possible solutions.
Similarly, putting
in the equation
, we get
Therefore,
is one of the infinite possible solutions.
Putting
in the equation
, we get
Therefore,
is one of the infinite possible solutions.
Putting
in the equation
, we get
Therefore,
is one of the infinite possible solutions.
Therefore, four different solutions for equation
are:
Now, we plot all these four points on the Cartesian plane. When we join these points, it makes a straight line.
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