The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.

**Solution:**

**Mean =** **units**

Modal class = (125-145)

Lower limit of the modal class

Size of the class interval

Frequency of the modal class

Frequency of the class proceeding the modal class

Frequency of the class succeeding the modal class

## Mode

## **units**

Number of consumers = 68

Cumulative frequency greater than is 42

So, median class = 125-145

# Median

where, l = lower limit of median class =125

n = number of observations =68

cf = cumulative frequency of class preceding the median class = 22

f = frequency of median class = 20

h = class size (assuming class size to be equal) = 20

## Median

## =125+12=137 units

Therefore, **mean = 137.05 units**, **mode = 135.76 units** and **median = 137 units** which are very close to each other.