**8.** From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest .

**Solution:**

Height of Cylinder =h =AO=**2.4 cm**

Diameter of Cylinder = **1.4 cm**

Radius of Cylinder = Radius of Cone = OB = r **cm**

**Using Pythagoras Theorem on to find Slant Height () of cone, we get**

**cm**

**Surface Area of remaining Solid = Surface Area of Cylinder Part + Inner surface Area of Hollow Cone **

** Total surface area of the remaining solid to the nearest** =18