Probability ncert solutions Chapter 15 Exercise 15.1 Question 13
13. A die is thrown once. Find the probability of getting
(i) a prime number (ii) a number lying between 2 and 6 (iii) an odd number
Solution (i)
Let E be the Event of getting a prime number with a single throw of dice.
Number of outcomes favorable to Event E=3 (There are three prime numbers from numbers 1 to 7 which are 2, 3 and 5.)
Total number of possible outcomes=6 {There are six possible outcomes in a dice.}
P(E)=(Number of outcomes favorable to Event E)/(Total number of possible outcomes)=3/6=1/2
Solution (ii)
Let F be the Event of getting a number between 2 and 6 with a single throw of dice.
Number of outcomes favorable to Event F=3 (There are 3 numbers between 2 and 6).
Total number of possible outcomes=6 {There are six possible outcomes in a dice.}
P(F)=(Number of outcomes favorable to Event F)/(Total number of possible outcomes)=3/6=1/2
Solution (iii)
Let A be the Event of getting an odd number with a single throw of dice.
Number of outcomes favorable to Event A=3 {There are 3 odd numbers from 1 to 6}
Total number of possible outcomes=6 {There are six possible outcomes in a dice}
P(A)=(Number of outcomes favorable to Event A)/Total number of possible outcomes=3/6=1/2
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