**Probability ncert solutions Chapter 15 Exercise 15.1 Question 13**

**13.** A die is thrown once. Find the probability of getting

(i) a prime number (ii) a number lying between 2 and 6 (iii) an odd number

**Solution (i)**

Let E be the Event of getting a prime number with a single throw of dice.

Number of outcomes favorable to Event E=3 (There are three prime numbers from numbers 1 to 7 which are 2, 3 and 5.)

Total number of possible outcomes=6 {There are six possible outcomes in a dice.}

P(E)=(Number of outcomes favorable to Event E)/(Total number of possible outcomes)=3/6=1/2

**Solution (ii)**

Let F be the Event of getting a number between 2 and 6 with a single throw of dice.

Number of outcomes favorable to Event F=3 (There are 3 numbers between 2 and 6).

Total number of possible outcomes=6 {There are six possible outcomes in a dice.}

P(F)=(Number of outcomes favorable to Event F)/(Total number of possible outcomes)=3/6=1/2

**Solution (iii)**

Let A be the Event of getting an odd number with a single throw of dice.

Number of outcomes favorable to Event A=3 {There are 3 odd numbers from 1 to 6}

Total number of possible outcomes=6 {There are six possible outcomes in a dice}

P(A)=(Number of outcomes favorable to Event A)/Total number of possible outcomes=3/6=1/2