**Areas related to Circles ncert solutions Chapter 12 Exercise 12.2 Question 6**

**6. **A chord of a circle of radius 15 cm subtends an angle of at the center. Find the areas of the corresponding minor and major segments. (Use and )

**Solution:**

**Area of minor segment ADB = Area of portion shaded in light blue color**

**= Area of minor sector - Area of**

- Area of **(1)**

In

**AO=OB {Radii of circle}**

{Angles opposite to equal sides are equal}

Also, we have {Angle sum property of triangle}

Therefore, we have which means that is an equilateral triangle.

**Area of equilateral triangle =**

** (2)**

Putting equation **(2)** in equation **(1)**, we get

**Area of minor segment ADB**

**Area of major segment = Area of circle - area of minor segment ADB**