**Applications of Trigonometry Heights and Distances Chapter 9 Exercise 9.1 Question 6**

**6. **A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30 to 60 as he walks towards the building. Find the distance he walked towards the building.

**Solution:**

We are given the height of tower (AF) = 30 m

The height of boy (BD) = 1.5 m

Therefore, AC = AF - BD = 30 -1.5 = 28.5 m

We want to find distance he walked towards the tower which is BG.

In , we have

m

In , we have

m

**BG=BC-GC m**

Therefore, he walks ** m** towards the tower.