Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 5
5. Given sec
=
. Calculate all other trigonometric ratios.
Solution:
sec
= (Hypotenuse) / (Side Adjacent to Angle
) = AC / BC
Let AC = 13k and BC = 12 k as we are given that sec
Using Pythagoras Theorem on
, we can say that
sin
= (Side Opposite to Angle
)/ Hypotenuse =
cos
= 1/sec
=
tan
= (Side Opposite to Angle
)/ (Side Adjacent to Angle
)
cot
= 1/tan
=
cosec
= 1/sin
zainab ali says
plz show video of this and explain it in detail.