**Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 5**

**5.** Given sec = . Calculate all other trigonometric ratios.

**Solution:**

sec = **(Hypotenuse)** / **(Side Adjacent to Angle ) = AC / BC**

**Let AC = 13k and BC = 12 k as we are given that sec **

Using Pythagoras Theorem on , we can say that

**sin ** = **(Side Opposite to Angle )/ Hypotenuse** =

**cos = 1/sec** ** = **

**tan = (Side Opposite to Angle )/ (Side Adjacent to Angle )**

**cot = 1/tan = **

**cosec = 1/sin **