Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 4
4. Given 15 cot A = 8, find sin A and sec A.
It is given that 15 cot A = 8
cot A = (Side Adjacent to Angle A) / (Side Opposite to Angle A)
Let AC = 8k and BC = 15k as we are given that
Applying Pythagoras Theorem on , we can say that
sin A = (side opposite to angle A) / (Hypotenuse) = BC / AB =
sec A = (Hypotenuse) / (side Adjacent to Angle A) = AB/AC =