**Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 4**

**4.** **Given** **15 cot A = 8**, **find** **sin A** **and** **sec A**.

**Solution:**

It is given that 15 cot A = 8

**cot A =** (**Side Adjacent to Angle A) / (Side Opposite to Angle A)**

Let AC = 8k and BC = 15k as we are given that

Applying **Pythagoras Theorem** on , we can say that

**sin A = (side opposite to angle A) / (Hypotenuse) = BC / AB =**

**sec A = (Hypotenuse) / (side Adjacent to Angle A) = AB/AC =**