**Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 3**

**3.** If, sin A = , find cos A and tan A.

**Solution:**

sin A = **opposite side to angle A / Hypotenuse** =

**Let BC = 3k and AC = 4k** because it is given that sin A =

**Using Pythagoras theorem** on , we can say that

cos A = **Adjacent side to angle A / Hypotenuse** = AB / AC =

tan A = (**Opposite side to angle A) / (Adjacent side to angle A)** = BC /AB