**Trigonometric Ratios CBSE NCERT Solutions Chapter 8 Exercise 8.1 Question 10**

**10.** In , right angled at Q, PR + QR = 25 cm And PQ = 5 cm. Determine the values of sin P, cos P and tan P.

**Solution:**

It is given that PR + QR = 25 cm

Let PR = x cm

Then, QR = (25 - x) cm

We are given that PQ = 5 cm

**Using Pythagoras Theorem on , we get**

{}

Therefore, PR = 13 cm

And, QR = (25 - x) = 25 - 13 = 12 cm

**sin P =** **(Side Opposite to Angle P) / (Hypotenuse)** =

**cos P =** **(Side Adjacent to Angle P) / (Hypotenuse)** =

**tan P =** **(Side Opposite to Angle P) / (Side Adjacent to Angle P)** =