Section Formula CBSE NCERT Solutions Chapter 7 Exercise 7.3 Question 3
3. Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, -1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.
Let A = (0, -1) = (x1, y1)
B = (2, 1) = (x2, y2)
C = (0, 3) = (x3, y3)
Area of =
P, Q and R are the mid-points of sides AB, AC and BC respectively.
Applying Section Formula to find the vertices of P, Q and R, we get
Applying same formula, Area of
Area cannot be in negative. Therefore, we only take the numerical value. Therefore, Area of =1 sq unit
(Area of )/(Area of ) = 1/4 =1:4