CBSE NCERT Solutions Chapter 6 Triangles Exercise 6.3 Question 7
7. In fig 6.38, altitudes AD and CE of
intersect each other at the point P. Show that:
(i)
~
(ii)
~
(iii)
~
(iv)
~
Solution (i)
In,
and
{Each 90 degrees}
(Vertically Opposite angles}
Therefore, by AA similarity criterion,
~
Solution (ii)
In,
and
{Common angle}
{Each 90 degrees}
Therefore, by AA similarity criterion,
~
Solution (iii)
In,
and
{Each 90 degrees}
{Common angle}
Therefore, by AA similarity criterion,
~
Solution (iv)
In
and
{Each 90 degrees}
(Common angle}
Therefore, by AA similarity criterion,
~
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