**Distance Formula CBSE NCERT solutions Chapter 7 Exercise 7.1 Question 7**

**7. **Find the point on the **x-axis** which is equidistant from** (2, -5) and (-2, 9)**.

**Solution:**

Let the point be **(x, 0)** on **x-axis** which is equidistant from **(2, -5)** and **(-2, 9)**.

Using **Distance Formula** and according to given conditions we have:

**Squaring both sides, we get**

**Therefore, point on the x-axis which is equidistant from (2, -5) and (-2, 9) is (-7, 0)**