CBSE NCERT Solutions Chapter 6 Triangles Exercise 6.5 Question 14
14. The perpendicular from A on side BC of a
intersects BC at D such that DB = 3CD. Prove that
Solution:
Given:
AD
BC and BD = 3CD.
To Prove:
Proof:
L.H.S =
{
by Pythagoras Theorem}
L.H.S =
{
by Pythagoras Theorem}}
L.H.S =
{BD = 3CD}
L.H.S =
(1)
We have BC = BD + CD = 3CD + CD = 4CD
(2)
Putting (2) in (1), we get
L.H.S =
= R.H.S
Hence Proved
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