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CBSE NCERT Solutions Chapter 6 Triangles Exercise 6.5 Question 11

CBSE NCERT Solutions Chapter 6 Triangles Exercise 6.5 Question 11


 

11 .    An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after 1\frac{1}{2} hours?

Solution:

Pythagoras Theorem cbse ncert solutions class 10

 

Distance traveled by aeroplane in 1\frac{1}{2} hrs towards North direction = 1000 \times \frac{3}{2} = 1500 km

Distance traveled by other aeroplane in 1\frac{1}{2} hrs towards West direction = 1200 \times \frac{3}{2} = 1800 km

 

We want to find distance (AC) between two aeroplanes after 1\frac{1}{2} hrs

 

Using Pythagoras theorem, we get

AC^2 = AB^2 + BC^2

\Rightarrow AC^2 = (1500)^2 + (1800)^2 = 2250000 + 3240000 = 5490000

\Rightarrow AC = \sqrt{5490000} = 300\sqrt{61} Km


 


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