CBSE NCERT Solutions Chapter 6 Triangles Exercise 6.2 Question 4
4. In fig, DE
AC and DF
AE. Prove that
Solution:
In
ABC, it is given that DE
AC.
Therefore,
{By Basic Proportionality theorem} (1)
In
ABE, it is given that DF
AE.
Therefore,
{By Basic Proportionality theorem} (2)
From (1) and (2), we can say that
Hence Proved
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