CBSE NCERT Solutions Chapter 5 Arithmetic Progressions Exercise 5.2 Question 11
11. Which term of the AP: 3, 15, 27, 39, … will be 132 more than its 54th term?
Solution:
Lets first calculate 54th of the given AP.
First term = a = 3
Common difference = d =15 – 3 = 12
Using formula
, to find nth term of arithmetic progression, we get
We want to find which term is 132 more than its 54th term. Lets suppose it is nth term which is 132 more than 54th term.
Therefore, we can say that
{
} {
}
Therefore, 65th term is 132 more than its 54th term.
Leave a Reply