**CBSE NCERT Solutions Chapter 5 Arithmetic Progressions Exercise 5.1 Question 2**

**2. Write first four terms of the AP, when the first term a and common difference d are given as follows:**

**(i) a = 10, d=10 (ii) a= -2, d=0**

**(iii) a=4, d=-3 (iv) a=-1, d= **

**(v) a=-1.25, d=-0.25**

**Solution (i)**

First term = a =10 , d=10

Second term = a+d = 10 + 10 = 20

Third term = second term + d = 20 + 10 = 30

Fourth term = third term + d = 30 + 10 = 40

**Therefore, first four terms are: 10, 20, 30, 40**

**Solution (ii) **

First term = a = -2 , d=0

Second term = a+d = -2 + 0 = -2

Third term = second term + d = -2 + 0 = -2

Fourth term = third term + d = -2 + 0 = -2

**Therefore, first four terms are: -2, -2, -2, -2**

**Solution (iii) **

First term = a = 4 , d=-3

Second term = a+d = 4 -3 = 1

Third term = second term + d = 1-3 = -2

Fourth term = third term + d = -2 -3 = -5

**Therefore, first four terms are: 4, 1, -2, -5**

**Solution (iv) **

First term = a = -1 , d=

Second term = a+d = -1+ =

Third term = second term + d = + = 0

Fourth term = third term + d = 0 + =

**Therefore, first four terms are: -1, , 0, **

**Solution (v) **

First term = a =-1.25 , d = -0.25

Second term = a+d = -1.25 - 0.25 = -1.50

Third term = second term + d = -1.50 -0.25 = -1.75

Fourth term = third term + d = -1.75 -0.25 = -2

**Therefore, first four terms are: -1.25, -1.50, -1.75, -2**