NCERT Chapter 4 Quadratic Equations Exercise 4.1 Q2 Download this solution
2. Represent the following situations in the form of Quadratic Equations:
(i) The area of rectangular plot is 528
. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.
Solution (i)
We are given that area of a rectangular plot is 528
.
Let breadth of rectangular plot be x metres
Length is one more than twice its breadth. Therefore length of rectangular plot is
metres
Area of rectangle = length x breadth
which is a Quadratic Equation.
(ii) The product of two consecutive numbers is 306. We need to find the integers.
Solution (ii)
Let two consecutive numbers be x and (x+1).
It is given that
which is a Quadratic Equation.
(iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) after 3 years will be 360. We would like to find Rohan’s present age.
Solution (iii)
Let present age of Rohan = x years
Let present age of Rohan’s mother = x +26 years
Age of Rohan after 3 years = (x+3) years
Age of Rohan’s mother after 3 years = x+26+3 = x+29 years
According to given condition:
which is a Quadratic Equation.
(iv) A train travels a distance of 480 km at uniform speed. If, the speed had been 8km/h less, then it would have taken 3 hours more to cover the same distance. We need to find speed of the train.
Solution (iv)
Let speed of train be x km/h
Time taken by train to cover 480 km =
hours
If, speed had been 8km/h less then time taken would be
hours
According to given condition, if speed had been 8km/h less then time taken is 3 hours less.
Therefore,
Dividing equation by 3, we get
which is a Quadratic Equation.
{Book has given Quadratic Equation in the form of u which is the same thing as
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