**NCERT Chapter 4 Quadratic Equations Exercise 4.1 Q2 Download this solution
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**2. Represent the following situations in the form of Quadratic Equations:**

**(i)** The area of rectangular plot is 528 . The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.

**Solution (i) **

We are given that area of a rectangular plot is 528 .

Let breadth of rectangular plot be x metres

Length is one more than twice its breadth. Therefore length of rectangular plot is metres

Area of rectangle = length x breadth

which is a **Quadratic Equation.**

**(ii)** The product of two consecutive numbers is 306. We need to find the integers.

**Solution (ii) **

Let two consecutive numbers be x and (x+1).

It is given that

which is a **Quadratic Equation.**

**(iii) **Rohan's mother is 26 years older than him. The product of their ages (in years) after 3 years will be 360. We would like to find Rohan's present age.

**Solution (iii) **

Let present age of Rohan = x years

Let present age of Rohan's mother = x +26 years

Age of Rohan after 3 years = (x+3) years

Age of Rohan's mother after 3 years = x+26+3 = x+29 years

According to given condition:

which is a** Quadratic Equation.**

**(iv)** A train travels a distance of 480 km at uniform speed. If, the speed had been 8km/h less, then it would have taken 3 hours more to cover the same distance. We need to find speed of the train.

**Solution (iv)**

Let speed of train be x km/h

Time taken by train to cover 480 km = hours

If, speed had been 8km/h less then time taken would be hours

According to given condition, if speed had been 8km/h less then time taken is 3 hours less.

Therefore,

Dividing equation by 3, we get

which is a **Quadratic Equation.**

{Book has given Quadratic Equation in the form of u which is the same thing as